HJ43 迷宫问题

深碍√TFBOYSˉ_ 2024-03-26 07:32 67阅读 0赞

> [牛客华为机试题库【题号 HJ开头】（重点看）][HJ]  
> [牛客在线编程算法篇【题号NC开头】][NC]  
> [剑指offer【题号 JZ开头】][offer_ JZ]  
> [力扣][Link 1]

### 1）[原题链接][Link 2] ###

### 2）已有题解 ###

### 3）代码 ###

package bfs;
    
    import java.io.BufferedReader;
    import java.io.IOException;
    import java.io.InputStreamReader;
    import java.util.Arrays;
    import java.util.Deque;
    import java.util.LinkedList;
    
    import static java.lang.System.in;
    
    /**
     * HJ43 迷宫问题
     */
    public class HJ43MazeProblem {
        
        public static void main(String[] args) throws IOException {
        
            BufferedReader bf = new BufferedReader(new InputStreamReader(in));
            int[] size = Arrays.stream(bf.readLine().split(" ")).mapToInt(Integer::parseInt).toArray();
            // 构造网格
            int row = size[0]; // 行
            int column = size[1]; // 列
            int[][] grid = new int[row][column];
            for (int i = 0; i < row; i++) {
        
                int[] col = Arrays.stream(bf.readLine().split(" ")).limit(column).mapToInt(Integer::parseInt).toArray();
                grid[i] = col;
            }
            bf.close();
    
            Point minDistance = getMinDistance(grid);
    
            Deque<int[]> res = new LinkedList<>();
            while (minDistance != null) {
        
                res.addFirst(getCoordinate(minDistance.row, minDistance.column));
                minDistance = minDistance.father;
            }
    
            res.stream().forEach(p -> System.out.println("(" + p[0] + "," + p[1] + ")"));
        }
    
    
        public static Point getMinDistance(int[][] grid) {
        
            Deque<Point> queue = new LinkedList<>(); // 队列记录下一步的所有情况
            boolean[][] visited = new boolean[grid.length][grid[0].length];//表示走过的位置，TRUE→走过，FALSE→没走过
    
            for (int i = 0; i < grid.length; i++) {
        
                for (int j = 0; j < grid[i].length; j++) {
        
                    if (i == 0 && j == 0) {
         // 表示找到入口,这里其实不用两层循环、只是练习一下这个思路
                        queue.add(getNode(i, j, null));
                        visited[i][j] = true;// 其实位置标记为已走过
                        break;
                    }
                }
            }
    
            int[][] nestStep = {
        {
        -1, 0}, {
        1, 0}, {
        0, -1}, {
        0, 1}}; // 上、下、左、右
    
            while (!queue.isEmpty()) {
        
                int queueSize = queue.size();
                for (int m = 0; m < queueSize; m++) {
        
                    Point poll = queue.poll();
                    for (int[] ints : nestStep) {
         // 上、下、左、右、四种可能性都遍历走一遍
                        int newX = poll.row + ints[0]; // 获取下一步的X坐标
                        int newY = poll.column + ints[1]; // 获取下一步的Y坐标
                        if (isValidInGrid(newX, newY, grid) && newX == grid.length - 1 && newY == grid[0].length - 1) {
         //范围内，如果下一步时出口的话，直接走一步出去
                            return getNode(newX, newY, poll); // 最后一个节点
                        }
                        if (isValidInGrid(newX, newY, grid) && !visited[newX][newY] && grid[newX][newY] == 0) {
        //范围内，没走过，不是障碍物
                            queue.add(getNode(newX, newY, poll));
                            visited[newX][newY] = true;//标记已经处理过
                        }
                    }
                }
            }
    
            return null; // 表示没找到
        }
    
        public static int[] getCoordinate(int i, int j) {
        
            return new int[]{
        i, j};
        }
    
        public static Point getNode(int i, int j, Point fatherNode) {
        
            return new Point(i, j, fatherNode);
        }
    
        public static boolean isValidInGrid(int i, int j, int[][] arr) {
        
            return 0 <= i && i < arr.length && 0 <= j && j < arr[i].length;
        }
    
    }
    
    class Point {
        
        int row;
        int column;
        Point father;
    
        Point(int px, int py, Point father) {
        
            this.row = px;
            this.column = py;
            this.father = father;
        }
    }

[HJ]: https://www.nowcoder.com/exam/oj/ta?tpId=37
[NC]: https://www.nowcoder.com/exam/oj
[offer_ JZ]: https://www.nowcoder.com/exam/oj/ta?page=1&tpId=13&type=13
[Link 1]: https://leetcode.cn/problemset/all/
[Link 2]: https://www.nowcoder.com/practice/cf24906056f4488c9ddb132f317e03bc?tpId=37&tqId=21266&rp=1&ru=/exam/oj/ta&qru=/exam/oj/ta&sourceUrl=/exam/oj/ta?page=1&pageSize=50&search=HJ43&tpId=37&type=37&difficulty=undefined&judgeStatus=undefined&tags=&title=HJ43