蓝桥杯基础练习BASIC-18 矩形面积交

末蓝、 2023-07-11 15:10 27阅读 0赞

## （C语言实现）IDE:dev c++ ##

### 算法一 ###

#include <stdio.h>
    double Area(double x1,double y1,double x2,double y2,double x3,double y3,double x4,double y4)
    { 
    	double s;
    	double x,y;
    	if(x4<=x1 || x2<=x3) x=0;
    	if(x3<=x1 && x1<=x4 && x4<=x2) x=x4-x1;
    	if(x3<=x1 && x1<=x2 && x2<=x4) x=x2-x1;
    	if(x1<=x3 && x3<=x4 && x4<=x2) x=x4-x3;
    	if(x1<=x3 && x3<=x2 && x2<=x4) x=x2-x3;
    	if(y4<=y1 || y2<=y3) y=0;
    	if(y3<=y1 && y1<=y4 && y4<=y2) y=y4-y1;
    	if(y3<=y1 && y1<=y2 && y2<=y4) y=y2-y1;
    	if(y1<=y3 && y3<=y4 && y4<=y2) y=y4-y3;
    	if(y1<=y3 && y3<=y2 && y2<=y4) y=y2-y3;	
    	s = x * y;
    	return s;
    }
    int main(){ 
    	double x1,y1, x2,y2, x3,y3, x4,y4, s;
    	scanf("%lf%lf%lf%lf%lf%lf%lf%lf",&x1,&y1,&x2,&y2,&x3,&y3,&x4,&y4);
    	s = Area(x1,y1, x2,y2, x3,y3, x4,y4);	
    	printf("%.2lf",s);	
    	return 0;
    }

### 算法二 ###

#include <stdio.h>
    int Area(double x1,double y1,double x2,double y2,double x3,double y3,double x4,double y4){ 
    	double s;
    	if(x4<=x1 || x2<=x3 || y4<=y1 || y2<= y3) s=0;
    	
    	if(x1<=x3 && x3<=x2 && x2<=x4 
    	&& y1<=y3 && y3<=y2 && y2<=y4) s=(x2-x3)*(y2-y3);
    	
    	if(x1<=x3 && x3<=x2 && x2<=x4 
    	&& y3<=y1 && y1<=y4 && y4<=y2) s=(x2-x3)*(y4-y1);
    	
    	if(x3<=x1 && x1<=x4 && x4<=x2
    	&& y3<=y1 && y1<=y4 && y4<=y2) s=(x4-x1)*(y4-y1);
    	
    	if(x3<=x1 && x1<=x4 && x4<=x2
    	&& y1<=y3 && y3<=y2 && y2<=y4) s=(x4-x1)*(y2-y3);
    	
    	if(x1<=x3 && x3<=x2 && x2<=x4
    	&& y1<=y3 && y3<=y4 && y4<=y2) s=(x2-x3)*(y4-y3);
    	
    	if(x1<=x3 && x3<=x4 && x4<=x2
    	&& y3<=y1 && y1<=y4 && y4<=y2) s=(x4-x3)*(y4-y1);
    	
    	if(x3<=x1 && x1<=x4 && x4<=x2
    	&& y1<=y3 && y3<=y4 && y4<=y2) s=(x4-x1)*(y4-y3);
    	
    	if(x1<=x3 && x3<=x4 && x4<=x2
    	&& y1<=y3 && y3<=y2 && y2<=y4) s=(x4-x3)*(y2-y3);
    	
    	if(x1<=x3 && x3<=x4 && x4<=x2
    	&& y1<=y3 && y3<=y4 && y4<=y2) s=(x4-x3)*(y4-y3);
    	
    	if(x3<=x1 && x1<=x2 && x2<=x4
    	&& y3<=y1 && y1<=y2 && y2<=y4) s=(x2-x1)*(y2-y1);
    	
    	if(x3<=x1 && x1<=x2 && x2<=x4
    	&& y1<=y3 && y3<=y4 && y4<=y2) s=(x2-x1)*(y4-y3);
    	
    	if(x1<=x3 && x3<=x4 && x4<=x2
    	&& y3<=y1 && y1<=y2 && y2<=y4) s=(x4-x3)*(y2-y1);
    	
    	if(x3<=x1 && x1<=x2 && x2<=x4
    	&& y1<=y3 && y3<=y2 && y2<=y4) s=(x2-x1)*(y2-y3);
    	
    	if(x1<=x3 && x3<=x2 && x2<=x4
    	&& y3<=y1 && y1<=y2 && y2<=y4) s=(x2-x3)*(y2-y1);
    	
    	if(x3<=x1 && x1<=x2 && x2<=x4
    	&& y3<=y1 && y1<=y4 && y4<=y2) s=(x2-x1)*(y4-y1);
    	
    	if(x3<=x1 && x1<=x4 && x4<=x2
    	&& y3<=y1 && y1<=y2 && y2<=y4) s=(x4-x1)*(y2-y1);
    	
    	return s;
    }
    int main(){ 
    	
    	double x1,y1, x2,y2, x3,y3, x4,y4, s;
    	scanf("%lf%lf%lf%lf%lf%lf%lf%lf",&x1,&y1,&x2,&y2,&x3,&y3,&x4,&y4);
    	
    	s = Area(x1,y1,x2,y2,x3,y3,x4,y4);
    	
    	printf("%0.2lf\n",s);
    
    	return 0;
    }

**如果这段代码对您有帮助，希望您可以给猿猿一个赞，谢谢您嘞，code不易，且看且珍惜。**