java计算时间差及比较时间大小

Love The Way You Lie 2024-02-19 13:55 26阅读 0赞

比如:现在是2004-03-26 13:31:40  
过去是:2004-01-02 11:30:24  
我现在要获得两个日期差,差的形式为:XX天XX小时XX分XX秒

方法一:  
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

try  
\{  
Date d1 = df.parse("2004-03-26 13:31:40");  
Date d2 = df.parse("2004-01-02 11:30:24");  
long diff = d1.getTime() - d2.getTime();  
long days = diff / (1000 \* 60 \* 60 \* 24);  
\}  
catch (Exception e)  
\{  
\}  
  
方法二:  
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");  
java.util.Date now = df.parse("2004-03-26 13:31:40");  
java.util.Date date=df.parse("2004-01-02 11:30:24");  
long l=now.getTime()-date.getTime();  
long day=l/(24\*60\*60\*1000);  
long hour=(l/(60\*60\*1000)-day\*24);  
long min=((l/(60\*1000))-day\*24\*60-hour\*60);  
long s=(l/1000-day\*24\*60\*60-hour\*60\*60-min\*60);  
System.out.println(""+day+"天"+hour+"小时"+min+"分"+s+"秒");  
  
方法三:  
SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");  
java.util.Date begin=dfs.parse("2004-01-02 11:30:24");  
java.util.Date end = dfs.parse("2004-03-26 13:31:40");  
long between=(end.getTime()-begin.getTime())/1000;//除以1000是为了转换成秒

long day1=between/(24\*3600);  
long hour1=between%(24\*3600)/3600;  
long minute1=between%3600/60;  
long second1=between%60/60;  
System.out.println(""+day1+"天"+hour1+"小时"+minute1+"分"+second1+"秒");

====================================================

java 比较时间大小

String s1="2008-01-25 09:12:09";  
String s2="2008-01-29 09:12:11";  
java.text.DateFormat df=new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss");  
java.util.Calendar c1=java.util.Calendar.getInstance();  
java.util.Calendar c2=java.util.Calendar.getInstance();  
try  
\{  
c1.setTime(df.parse(s1));  
c2.setTime(df.parse(s2));  
\}catch(java.text.ParseException e)\{  
System.err.println("格式不正确");  
\}  
int result=c1.compareTo(c2);  
if(result==0)  
System.out.println("c1相等c2");  
else if(result<0)  
System.out.println("c1小于c2");  
else  
System.out.println("c1大于c2");