Stream流中将集合转成map

蔚落 2023-10-03 14:08 31阅读 0赞

public Map<Long, String> findBusinessUnitMapBySoids(List<Long> businessUnitSoids) {
        
            ListResult<List<BusinessUnitVo>> listBySoids = iBusinessUnitApi.findListBySoids(businessUnitSoids);
            Map<Long, String> res = new ConcurrentHashMap<>();
            if (ObjectUtils.isEmpty(listBySoids) || ObjectUtils.isEmpty(listBySoids.getData())) {
        
                return res;
            } else {
        
                List<BusinessUnitVo> BusinessUnitVos = listBySoids.getData();
                res = BusinessUnitVos.stream().filter(ObjectUtil::isNotEmpty)
                        .filter(a -> ObjectUtil.isNotEmpty(a.getBusinessUnitSoid()))
                        .filter(a -> ObjectUtil.isNotEmpty(a.getBusinessUnitName()))
                        .collect(Collectors.toMap(a -> a.getBusinessUnitSoid(), BusinessUnitVo::getBusinessUnitName, (key1, key2) -> key2));
            }
            return res;
        }

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public Map<String, OppBasicData> OppBasicDataMap(Boolean updateFlag) {
        
            LambdaQueryWrapper<OppBasicData> queryWrapper=new LambdaQueryWrapper<>();
            queryWrapper.eq(OppBasicData::getUpdateFlag,updateFlag);
            Map<String, OppBasicData> stringOppBasicDataMap = Optional.ofNullable(list(queryWrapper))
                    .map(list -> list.stream()
                            .filter(oppBasicData -> ObjectUtils.isNotEmpty(oppBasicData.getOppCode()))
                            .collect(Collectors.toMap(OppBasicData::getOppCode, Function.identity(), (key1, key2) -> key2)))
                    .orElse(new HashMap<>());
            return stringOppBasicDataMap;
        }

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