html写的玫瑰花

以你之姓@ 2023-07-07 11:19 32阅读 0赞

网上摘抄，自己又修修补补，添点小东西：

<!DOCTYPE html>
    <html lang="en">
    <head>
        <meta charset="UTF-8">
     <title>情人节快乐</title>
    
     
     <meta name="Generator" content="EditPlus">
     <meta name="Author" content="">
     <meta name="Keywords" content="">
     <meta name="Description" content="">
     </head>
     <body>
        
    <div id="demo" style="width:520; height:500px;"><canvas id="c" height="500" width="500"></canvas></div>
    <audio autoplay="autoplay" loop="loop" controls="controls">
        <source src="123.mp3" type="audio/mpeg" />
      Your browser does not support the audio element.
      </audio>
      <button id="rese" onclick="clear_canvas()" hidden></button>
    <script> 
      var b = document.body;
      var c = document.getElementsByTagName('canvas')[0];
      var a = c.getContext('2d');
      var canvas = document.getElementsByTagName('canvas')[0];
      var ctx = canvas.getContext('2d');
      document.body.clientWidth; 
      with(m=Math)C=cos,S=sin,P=pow,R=random;
      c.width=c.height=f=500;h=-250;
      function p(a,b,c){ 
        if(c>60)
          return[S(a*7)*(13+5/(.2+P(b*4,4)))-S(b)*50,b*f+50,625+C(a*7)*(13+5/(.2+P(b*4,4)))+b*400,a*1-b/2,a];
        A=a*2-1;
        B=b*2-1;
        if(A*A+B*B<1)
        { 
          if(c>37)
          { 
            n=(j=c&1)?6:4;o=.5/(a+.01)+C(b*125)*3-a*300;
            w=b*h;
            return[o*C(n)+w*S(n)+j*610-390,o*S(n)-w*C(n)+550-j*350,1180+C(B+A)*99-j*300,.4-a*.1+P(1-B*B,-h*6)*.15-a*b*.4+C(a+b)/5+P(C((o*(a+1)+(B>0?w:-w))/25),30)*.1*(1-B*B),o/1e3+.7-o*w*3e-6]
          }
          if(c>32)
          { 
            c=c*1.16-.15;o=a*45-20;w=b*b*h;z=o*S(c)+w*C(c)+620;
            return[o*C(c)-w*S(c),28+C(B*.5)*99-b*b*b*60-z/2-h,z,(b*b*.3+P((1-(A*A)),7)*.15+.3)*b,b*.7]
          }
          o=A*(2-b)*(80-c*2);
          w=99-C(A)*120-C(b)*(-h-c*4.9)+C(P(1-b,7))*50+c*2;z=o*S(c)+w*C(c)+700;
          return[o*C(c)-w*S(c),B*99-C(P(b, 7))*50-c/3-z/1.35+450,z,(1-b/1.2)*.9+a*.1, P((1-b),20)/4+.05]
        }
      }
      var draw = setInterval('for(i=0;i<100000;i++)if(s=p(R(),R(),i%46/.74)){z=s[2];x=~~(s[0]*f/z-h);y=~~(s[1]*f/z-h);if(!m[q=y*f+x]|m[q]>z)m[q]=z,a.fillStyle="rgb("+~(s[3]*h)+","+~(s[4]*h)+","+~(s[3]*s[3]*-80)+")",a.fillRect(x,y,1,1)}',0);
      var demo = document.getElementById('demo');
      function redraw(){ 
        /* var d_c = document.createElement("canvas"); d_c.setAttribute("id","c"); d_c.setAttribute("width","520"); d_c.setAttribute("height","500"); demo.appendChild(d_c); */
        draw = setInterval('for(i=0;i<100000;i++)if(s=p(R(),R(),i%46/.74)){z=s[2];x=~~(s[0]*f/z-h);y=~~(s[1]*f/z-h);if(!m[q=y*f+x]|m[q]>z)m[q]=z,a.fillStyle="rgb("+~(s[3]*h)+","+~(s[4]*h)+","+~(s[3]*s[3]*-80)+")",a.fillRect(x,y,1,1)}',0);
        //alert(d_c);
      }
      function clear_canvas()
      { 
        ctx.clearRect(0,0,520,500);
        //canvas.parentNode.removeChild(canvas); //删除
      }
      function stop_draw(obj){ 
            clear_canvas(obj);
      }
    window.onload = function(){ 
        document.getElementById('rese').click();
    }
    </script>
     </body>
    </html>

效果图(是比我自己弄的好看)：  
![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3FxXzE5Njc0MjYz_size_16_color_FFFFFF_t_70]

[watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3FxXzE5Njc0MjYz_size_16_color_FFFFFF_t_70]: https://img-blog.csdnimg.cn/2020022222521741.png?x-oss-process=image/watermark,type_ZmFuZ3poZW5naGVpdGk,shadow_10,text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3FxXzE5Njc0MjYz,size_16,color_FFFFFF,t_70