python 基础系列07-字典集合

女爷i 2023-07-06 06:30 43阅读 0赞

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#python 基础系列07-字典集合
    
    #引入sys库
    import sys
    import copy
    
    if __name__ == '__main__':
        a,b,c =1,2,3
    
        #字段的访问效率速度要优于集合跟元组，字典是无序的，是可变的
        mydict = {1:'a111',2:'bccc'}
        print(type(mydict))
        print(mydict[1],mydict[2])
    
        #创建字典 方式一
        dict1 = dict((['1','2'],['aa','bb']))
        print(dict1) #{1: 2, 'aa': 'bb'}
    
        # 创建字典 方式二
        dict2 = dict.fromkeys([1,2,3,4],'xxxx')
        dict3 = dict.fromkeys('abcd','xxxx')
        print(dict2)#{1: 'xxxx', 2: 'xxxx', 3: 'xxxx', 4: 'xxxx'}
        print(dict3) #{'a': 'xxxx', 'b': 'xxxx', 'c': 'xxxx', 'd': 'xxxx'}
    
        #字典获取参数值
        print(dict1.keys()) #dict_keys([1, 'aa'])
        print(dict1.values()) #dict_values([2, 'bb'])
        print(dict1['1'],dict1['aa'])
        #循环
        for var in dict1:
            print(var)
        #判断key是否存在 ,不能判断value值
        print('1' in dict1)
    
        #删除值
        del  mydict[1]
        print(mydict)
    
        #pop 函数删除值 并保持值
        rs  = mydict.pop(2)
        print(mydict) # {}
        print(rs) #bccc
    
        #清空字典
        mydict.clear()
    
    
        #集合set 分为可变跟不可变集合 ,集合是去重的类似set,集合是乱序的
    
        myset = {'a','b','c','d','d'}
        myset2 = set([1,2,3,4])
        print(myset)
    
        #创建不可变集合
        myset_no = frozenset([1,2,34,5,6])
    
        #循环访问值
        for  i in myset:
            print(i)
    
        #更新集合 #不可变集合不能更新
        myset.add(('1','2'))
        print(myset)
        myset.update(('112aa','hhhh')) #{'b', '112aa', 'hhhh', ('1', '2'), 'a', 'c', 'd'}
        print(myset)
        #判断是否在
        print('a' in  myset)
        #删除集合
        #myset.remove()
        #del myset
    
        #判断交集和子集
        myset < myset #前者是否是后者的子集
        myset > myset #前者是否是后者的超集
    
        #集合跟集合联合 交集 差补 对称差分
        myset | myset
        myset & myset
        myset - myset
        myset ^ myset

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