将gps左边转成百度坐标，js方法，java方法。

ゝ一纸荒年。 2023-06-29 15:54 25阅读 0赞

js转换方法

java转换方法

public static void main(String[] args) {
    //        double[] local = GpsToBaiDuXY.wgs2bd(126.50111324097671,45.88024762976107);126.488445 45.871875
            double[] local = GpsToBaiDuXY.wgs2bd(45.871875,126.488445);
            System.out.println(local[0]);
            System.out.println(local[1]);
        }
        
        static double pi = 3.14159265358979324;
        static double a = 6378245.0;
        static double ee = 0.00669342162296594323;
        public final static double x_pi = 3.14159265358979324 * 3000.0 / 180.0;
     
        public static double[] wgs2bd(double lat, double lon) {
               double[] wgs2gcj = wgs2gcj(lat, lon);
               double[] gcj2bd = gcj2bd(wgs2gcj[0], wgs2gcj[1]);
               return gcj2bd;
        }
     
        public static double[] gcj2bd(double lat, double lon) {
               double x = lon, y = lat;
               double z = Math.sqrt(x * x + y * y) + 0.00002 * Math.sin(y * x_pi);
               double theta = Math.atan2(y, x) + 0.000003 * Math.cos(x * x_pi);
               double bd_lon = z * Math.cos(theta) + 0.0065;
               double bd_lat = z * Math.sin(theta) + 0.006;
               return new double[] { bd_lat, bd_lon };
        }
     
        public static double[] bd2gcj(double lat, double lon) {
               double x = lon - 0.0065, y = lat - 0.006;
               double z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * x_pi);
               double theta = Math.atan2(y, x) - 0.000003 * Math.cos(x * x_pi);
               double gg_lon = z * Math.cos(theta);
               double gg_lat = z * Math.sin(theta);
               return new double[] { gg_lat, gg_lon };
        }
     
        public static double[] wgs2gcj(double lat, double lon) {
               double dLat = transformLat(lon - 105.0, lat - 35.0);
               double dLon = transformLon(lon - 105.0, lat - 35.0);
               double radLat = lat / 180.0 * pi;
               double magic = Math.sin(radLat);
               magic = 1 - ee * magic * magic;
               double sqrtMagic = Math.sqrt(magic);
               dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
               dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);
               double mgLat = lat + dLat;
               double mgLon = lon + dLon;
               double[] loc = { mgLat, mgLon };
               return loc;
        }
     
        private static double transformLat(double lat, double lon) {
               double ret = -100.0 + 2.0 * lat + 3.0 * lon + 0.2 * lon * lon + 0.1 * lat * lon + 0.2 * Math.sqrt(Math.abs(lat));
               ret += (20.0 * Math.sin(6.0 * lat * pi) + 20.0 * Math.sin(2.0 * lat * pi)) * 2.0 / 3.0;
               ret += (20.0 * Math.sin(lon * pi) + 40.0 * Math.sin(lon / 3.0 * pi)) * 2.0 / 3.0;
               ret += (160.0 * Math.sin(lon / 12.0 * pi) + 320 * Math.sin(lon * pi  / 30.0)) * 2.0 / 3.0;
               return ret;
        }
     
        private static double transformLon(double lat, double lon) {
               double ret = 300.0 + lat + 2.0 * lon + 0.1 * lat * lat + 0.1 * lat * lon + 0.1 * Math.sqrt(Math.abs(lat));
               ret += (20.0 * Math.sin(6.0 * lat * pi) + 20.0 * Math.sin(2.0 * lat * pi)) * 2.0 / 3.0;
               ret += (20.0 * Math.sin(lat * pi) + 40.0 * Math.sin(lat / 3.0 * pi)) * 2.0 / 3.0;
               ret += (150.0 * Math.sin(lat / 12.0 * pi) + 300.0 * Math.sin(lat / 30.0 * pi)) * 2.0 / 3.0;
               return ret;
        }