Python—— jieba中文分词库 + 文本中文的名字词频统计，有意思没？

川长思鸟来 2023-02-28 01:59 53阅读 0赞

**jieba是优秀的中文分词第三方库**

*  中文文本需要通过分词获得单个的词语；
 *  jieba是优秀的中文分词第三方库，需要额外安装；
 *  jieba库提供三种分词模式，最简单只需掌握一个函数。

(cmd命令行) pip install jieba

**jieba分词的三种模式**  
精确模式、全模式、搜索引擎模式

*  精确模式：把文本精确的切分开，不存在冗余单词；
 *  全模式：把文本中所有可能的词语都扫描出来，有冗余；
 *  搜索引擎模式：在精确模式基础上，对长词再次切分。  
    ![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDc3NTI1NQ_size_16_color_FFFFFF_t_70]  
    ![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDc3NTI1NQ_size_16_color_FFFFFF_t_70 1]  
    代码版本1 ：

import jieba
    txt = open("threekingdoms.txt", "r", encoding='utf-8').read()
    words  = jieba.lcut(txt) # jieba库方法 把文本转换为单词列表，方便统计
    counts = {
        }
    for word in words:
        if len(word) == 1: # 去符号，单字
            continue
        else:
            counts[word] = counts.get(word,0) + 1 # 统计词频
    items = list(counts.items())
    for i in range(15):
        items.sort(key=lambda x:x[1], reverse=True)
        word, count = items[i]
        print ("{0:<10}{1:>5}".format(word, count))
    
    会发现结果并不如意，有些输出文字重复了。

以上代码看的不懂？ 这里有详细解释，外加另一道题的理解哟，点击下方**连接**  
[**Python**——如何进行文本词频统计][Python]  
![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDc3NTI1NQ_size_16_color_FFFFFF_t_70 2]  
代码版本2：

import jieba
    excludes = {
        "将军","却说","荆州","二人","不可","不能","如此","丞相"}
    
    txt = open("threekingdoms.txt", "r", encoding='utf-8').read()
    words  = jieba.lcut(txt)
    counts = {
        }
    for word in words:
        if len(word) == 1:
            continue
        elif word == "诸葛亮" or word == "孔明曰":
            rword = "孔明"
        elif word == "关公" or word == "云长":
            rword = "关羽"
        elif word == "玄德" or word == "玄德曰":
            rword = "刘备"
        elif word == "孟德":
            rword = "曹操"
        else:
            rword = word
        counts[rword] = counts.get(rword,0) + 1
    
    for word in excludes: # 删掉excludes里的词
        del counts[word]
    items = list(counts.items())
    items.sort(key=lambda x:x[1], reverse=True) 
    for i in range(5):
        word, count = items[i]
        print ("{0:<10}{1:>5}".format(word, count))

![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDc3NTI1NQ_size_16_color_FFFFFF_t_70 3]

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[Python]: https://blog.csdn.net/weixin_44775255/article/details/107445950
[watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDc3NTI1NQ_size_16_color_FFFFFF_t_70 2]: /images/20230209/6a9c301f36934c8eabdd0f99e4d5fe6b.png
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