python实现鼠标手动截图(类似于QQ截图)

迈不过友情╰ 2022-11-28 00:58 409阅读 0赞

由于在网上找了很久，只找到按像素位置截图和全屏截图的，所以决定自己写一个。  
本程序实现原理是现用PIL里的ImageGrab进行全屏截图，然后通过模拟鼠标操作，进行截图，最后删除全屏截图，只留下鼠标截图  
**代码如下:**

import cv2
    import time,PIL,os
    from PIL import ImageGrab
    import numpy as np
    #截图
    def cut():
        global img
        scrren_cut()
        img = cv2.imread('screen.jpg')
        cv2.namedWindow('image')
        cv2.setMouseCallback('image', on_mouse)
        cv2.imshow('image', img)
        cv2.waitKey(0)
        os.remove('screen.jpg')
    def scrren_cut():
        beg = time.time()
        debug = False
        # img = ImageGrab.grab(bbox=(250, 161, 1141, 610))
        image = ImageGrab.grab()
        image.save("screen.jpg")
        # PIL image to OpenCV image
    def on_mouse(event, x, y, flags, param):
        global img, point1, point2
        img2 = img.copy()
        if event == cv2.EVENT_LBUTTONDOWN:         #左键点击
            point1 = (x,y)
            cv2.circle(img2, point1, 10, (0,255,0), 5)
            cv2.imshow('image', img2)
        elif event == cv2.EVENT_MOUSEMOVE and (flags & cv2.EVENT_FLAG_LBUTTON):               #按住左键拖曳
            cv2.rectangle(img2, point1, (x,y), (255,0,0), 5)
            cv2.imshow('image', img2)
        elif event == cv2.EVENT_LBUTTONUP:         #左键释放
            point2 = (x,y)
            cv2.rectangle(img2, point1, point2, (0,0,255), 5) 
            cv2.imshow('image', img2)
            min_x = min(point1[0],point2[0])     
            min_y = min(point1[1],point2[1])
            width = abs(point1[0] - point2[0])
            height = abs(point1[1] -point2[1])
            cut_img = img[min_y:min_y+height, min_x:min_x+width]
            cv2.imwrite('cut.jpg', cut_img)