Jackson 学习笔记 XML转JSON

心已赠人 2022-10-09 00:40 277阅读 0赞

### Jackson 学习笔记 XML转JSON ###

*  依赖
 *  示例
 *  XML > JavaBean > Json
 *  XML > JsonNode

利用`jackson`实现 xml 2 json。

# 依赖 #

`SpringBoot` 项目自带了 `jackson-databind` 省略。只需要添加`jackson-dataformat-xml`即可。另外`version`也可以省掉。

<dependency>
             <groupId>com.fasterxml.jackson.core</groupId>
             <artifactId>jackson-databind</artifactId>
             <version>2.12.3</version>
         </dependency>
    	<dependency>
           <groupId>com.fasterxml.jackson.dataformat</groupId>
           <artifactId>jackson-dataformat-xml</artifactId>
           <version>2.12.3</version>
       </dependency>

# 示例 #

# XML > JavaBean > Json #

常规思路，先将XML转成 Java对象，再转为 Json

@Test
        void xml2json1() throws JsonProcessingException { 
            XmlMapper xmlMapper = new XmlMapper();               
            String xml = "<Hero><name>张三</name><age>18</age></Hero>";
            Hero hero = xmlMapper.readValue(xml, Hero.class);
            
            ObjectMapper mapper = new ObjectMapper();
            String json = mapper.writeValueAsString(hero);
            System.out.println(json);
        }

# XML > JsonNode #

直接将 `XML字符串`转为 `Json对象`。省掉中间的`Java对象`。

@Test
        void xml2json2() throws IOException { 
            XmlMapper xmlMapper = new XmlMapper();
            String xml = "<Hero><name>张三</name><age>18</age></Hero>";
            JsonNode jsonNode = xmlMapper.readTree(xml.getBytes());
    
            System.out.println(jsonNode.get("name").asText("无名"));
            System.out.println(jsonNode.get("age").asInt(99));
            System.out.println(jsonNode.get("title"));        
        }