Python对比两个文件夹的文件差异并导出差异

浅浅的花香味﹌ 2022-09-16 14:17 427阅读 0赞

python脚本：

# -*-coding:utf-8-*-    
      
    #===============================================================================  
    # 目录对比工具(包含子目录 )，并列出
    # 1、A比B多了哪些文件  
    # 2、B比A多了哪些文件  
    # 3、二者相同的文件: md5比较
    #===============================================================================  
      
    import os
    import time
    import difflib
    import hashlib
    import shutil
    
    
    def getFileMd5(filename):
        if not os.path.isfile(filename):
            print('file not exist: ' + filename)
            return
        myhash = hashlib.md5()
        f = open(filename,'rb')
        while True:
            b = f.read(8096)
            if not b :
                break
            myhash.update(b)
        f.close()
        return myhash.hexdigest()
    
    
    def getAllFiles(path):
        flist=[]
        for root, dirs , fs in os.walk(path):
            for f in fs:
                f_fullpath = os.path.join(root, f)
                f_relativepath = f_fullpath[len(path):]
                flist.append(f_relativepath)
        return flist
    
    def dirCompare(comparePath,targetPath):
        afiles = getAllFiles(comparePath)
        bfiles = getAllFiles(targetPath)
    
        setA = set(afiles)
        setB = set(bfiles)
    
        commonfiles = setA & setB  # 处理共有文件
    
        for of in sorted(commonfiles):
            amd=getFileMd5(comparePath+'\\'+of)
            bmd=getFileMd5(comparePath+'\\'+of)
            if amd != bmd:  
                if not os.path.exists(os.path.dirname(os.getcwd() + of)):
                    os.makedirs(os.path.dirname(os.getcwd() + of))
                # 将文件保存在执行此脚本的目录...
                shutil.copyfile(targetPath + of, os.getcwd() + of)
    
        # 处理仅出现在一个目录中的文件
        onlyFiles = setA ^ setB
        onlyInA = []
        onlyInB = []
        for of in onlyFiles:
            if of in afiles:
                onlyInA.append(of)
            elif of in bfiles:
                onlyInB.append(of)
                
        if len(onlyInA) > 0:
            print ('-' * 20,"only in ", comparePath, '-' * 20)
            for of in sorted(onlyInA):
                print (of)
                # 不保存comparePath多出来的文件...
                
        if len(onlyInB) > 0:
            print ('-' * 20,"only in ", targetPath, '-' * 20)
            for of in sorted(onlyInB):
                print (of)
                if not os.path.exists(os.path.dirname(os.getcwd() + of)):
                    os.makedirs(os.path.dirname(os.getcwd() + of))
                # 将文件保存在执行此脚本的目录...
                shutil.copyfile(targetPath + of, os.getcwd() + of)
                
    if __name__ == '__main__':
        comparePath = 'D:\\test1\\assets' #对比文件夹
        targetPath = 'D:\\test2\\assets' #参考文件夹
        savePath = 'D:\\test3\\assets' #保存文件夹，在这里我没保存到savePath，大家如果需要保存，可以把脚本中的os.getcwd()替换为savePath
        dirCompare(comparePath, targetPath)
        print("\ndone!")

参考文章：[https://blog.csdn.net/linxinfa/article/details/90240952][https_blog.csdn.net_linxinfa_article_details_90240952]

[https_blog.csdn.net_linxinfa_article_details_90240952]: https://blog.csdn.net/linxinfa/article/details/90240952