Python操作Neo4j的基本操作

ゞ浴缸里的玫瑰 2022-06-09 11:21 367阅读 0赞

## 1.下载Neo4j数据库 ##

> 官网：[https://neo4j.com/download-thanks/?edition=community&release=3.2.3&flavour=winstall64][https_neo4j.com_download-thanks_edition_community_release_3.2.3_flavour_winstall64]  
> 注：可能会下的很慢  
> 百度云：链接: [https://pan.baidu.com/s/1o8gGB38][https_pan.baidu.com_s_1o8gGB38] 密码: 9hn2

## 2.安装 ##

> 注：初次登陆username和password 默认都为neo4j

Neo4j原生语句：  
1. 创建一个节点：  
语法:CREATE (node-name:label-name\{Property1-name:Property1-Value,…Propertyn-name:Propertyn-Value\})  
create(江湖流派:明教\{name:’张无忌’,skill:’九阳真经’\}

2. 为两个节点建立关系：
        语法:CREATE(node1:label1)-[relationship-name:relationship-label-name]->(node2:label2)
        match(p:武当),(s:明教) where p.name = '张翠山' and s.name = '张无忌' create (p)-[r:父子]->(s)   //为两个节点建立关系
        match(p1:峨眉派),(p2:峨眉派) where p1.name = '灭绝师太' and p2.name = '周芷若' create (p1)-[r:师徒]->(p2) return r   //为两个节点建立关系,并返回关系图
    
    3. 根据指定关系和节点查找关系图：
    
         语法:match R=(node1:label1)-[relationship-name:relationship-label-name]->(p2) return R
               match R=(p1:峨眉派)-[r:师徒]->(p2) return R   //返回峨眉派具有师徒关系的节点图
    
    4. 删除两个节点的指定关系：
        语法:MATCH (node1:label1{Property1:Value1})-[relationship-name:relationship-label-name]->(node2:label2{Property2:Value2}) delete r
        如：由于宋青书背叛武当,宋远桥和他断绝了父子关系
        MATCH (p1:武当{name:'宋远桥'})-[r:父子]->(p2:武当{name:'宋青书'}) delete r

## 3.python引入py2neo库 ##

## 4.基础操作 ##

from py2neo import Graph, Node, Relationship
    
        # 连接neo4j数据库
        graph = Graph("http://127.0.0.1:7474";,username="neo4j",password="123456")
        # 创建结点：label结点，方便以后的结点查找操作
        temp_node1 = Node(lable="Person",name="node1")
        temp_node2 = Node(lable="Person",name="node2")
        graph.create(temp_node1)
        graph.create(temp_node2)
        # 建立关系
        node_1_call_node_2 = Relationship(temp_node1,'CALL',temp_node2)
        node_1_call_node_2['count'] = 1
        node_2_call_node_1 = Relationship(temp_node2,'CALL',temp_node1)
        graph.create(node_2_call_node_1)
        graph.create(node_1_call_node_2)
        # 更新关系或节点的属性 push提交
        node_1_call_node_2['count']+=1
        graph.push(node_1_call_node_2)
    
        # 通过属性值来查找节点和关系find_one
        find_code = graph.find_one(
        label="明教",
        property_key="name",
        property_value="张无忌"
        )
        print(find_code['name'])
    
        # find方法已被弃用：通过属性值来查找所有节点和关系find替换为：NodeSelector
        find = NodeSelector(graph).select('明教')
        for f in find:
            print(f['name'])

## 参考博客： ##

> [http://www.cnblogs.com/iaknehc/p/7096732.html][http_www.cnblogs.com_iaknehc_p_7096732.html]  
> [http://blog.csdn.net/wrzcy/article/details/51905977][http_blog.csdn.net_wrzcy_article_details_51905977]

[https_neo4j.com_download-thanks_edition_community_release_3.2.3_flavour_winstall64]: https://neo4j.com/download-thanks/?edition=community&release=3.2.3&flavour=winstall64
[https_pan.baidu.com_s_1o8gGB38]: https://pan.baidu.com/s/1o8gGB38
[http_www.cnblogs.com_iaknehc_p_7096732.html]: http://www.cnblogs.com/iaknehc/p/7096732.html
[http_blog.csdn.net_wrzcy_article_details_51905977]: http://blog.csdn.net/wrzcy/article/details/51905977