hql查询字段和查询后放入list中的顺序不一样？！？ [

ゝ一世哀愁。 2022-05-23 11:36 274阅读 0赞

# hql查询字段和查询后放入list中的顺序不一样？！？ \[问题点数：20分\] #

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     <div style="list-style:none;margin:10px 0px;padding:0px;border:none;font-size:12px;"></div>写一个数据导出excel，自己也不太懂，参照着写的，功能可以实现，就是这段程序看不懂，请各位指点一二！ 
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     <span>发表于： 2015-10-20 21:43:40&nbsp;</span> 
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      引用&nbsp;1&nbsp;楼&nbsp;baidu_32174073的回复: 
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       这是迭代器迭代。。。next（）是迭代本次的值，顺便迭代加一 
     </blockquote>额，这样呀。那上面为什么hql查询字段的顺序和放入list中的顺序不一样呀。。 
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     <span>回复于： 2015-10-21 07:03:09&nbsp;</span> 
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      map的key是无序的，要想和list中的一样，可以用LinkedHashMap 
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     <span>回复于： 2015-10-21 09:07:45</span> 
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    <div style="list-style:none;margin:0px;padding:16px;border:none;line-height:28px;width:758px;">
      引用&nbsp;4&nbsp;楼&nbsp;时尚程序员的回复: 
     <blockquote style="padding:0px;margin-bottom:0px;font-size:14px;border:none;list-style:none;">
       楼主应该遍历map获取到值了再动态增加where条件，最后用HibernateTemplate实现查询。 
     </blockquote>可是它返回的是query.list，这不是代表它应该是一个list吗？ 
     <br>&nbsp;&nbsp;&nbsp;&nbsp;请多指点，白痴问题还请谅解。。 
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     <span>回复于： 2015-10-22 08:53:47&nbsp;</span> 
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      我又仔细看了下，原来楼主不是查询条件的顺序错了，是读取返回结果时出问题了啊。你既然知道了你查的是哪些字段，你就知道map中放了哪些key了，直接使用map.get("org_id")这样就可以了啊 
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      <li style="list-style:none;margin-top:0px;margin-left:0px;padding:0px;border:none;width:820px;line-height:25px;white-space:nowrap;"><a href="https://blog.csdn.net/rhjetjdfgjr/article/details/38296787" title="根据表中某个字段的首字母进行分类查询" style="background:transparent;color:rgb(51,90,164);" rel="nofollow">根据表中某个字段的首字母进行分类查询</a></li> 
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     <span>回复于： 2015-10-22 10:05:54</span> 
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    <div style="list-style:none;margin:0px;padding:16px;border:none;line-height:28px;width:758px;">
      引用&nbsp;6&nbsp;楼&nbsp;时尚程序员的回复: 
     <blockquote style="padding:0px;margin-bottom:0px;font-size:14px;border:none;list-style:none;">
       我又仔细看了下，原来楼主不是查询条件的顺序错了，是读取返回结果时出问题了啊。你既然知道了你查的是哪些字段，你就知道map中放了哪些key了，直接使用map.get("org_id")这样就可以了啊 
     </blockquote>不好意思，我不太理解您的意思。读取返回结果时出错了，指的是哪一步呀。。。然后您说的使用map.get()，可是map中有很多条记录，一条记录很多字段，而还需要分页。。。。不太懂。。。。 
     <br> 
     <br> 
     <br> 
     <br>&nbsp;&nbsp;&nbsp;&nbsp;白痴问题还请见谅 
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      <li style="list-style:none;margin-top:0px;margin-left:0px;padding:0px;border:none;width:820px;line-height:25px;white-space:nowrap;"><a href="https://blog.csdn.net/houpengfei111/article/details/9195787" title="hql 使用in elements 进行多对多查询" style="background:transparent;color:rgb(51,90,164);" rel="nofollow">hql 使用in elements 进行多对多查询</a></li> 
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     <span>回复于： 2015-10-22 14:47:21&nbsp;</span> 
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    <div style="list-style:none;margin:0px;padding:16px;border:none;line-height:28px;width:758px;">
      你用Hibernate查询的是一个list&lt;Map&gt;类型，你直接遍历你的list就可以获得一个一个的单条记录，单条记录是map类型，map里面的key值就是hql语句中的字段别名，你在遍历list的时候。 
     <br>&nbsp;&nbsp;if(list!=null&amp;&amp;!list.isEmpty()){ 
     <br>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;for(Map&nbsp;map:list){ 
     <br>&nbsp;&nbsp;&nbsp; 
     <br>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;Object&nbsp;&nbsp;o=&nbsp;map.get("org_id"); 
     <br>&nbsp;&nbsp;.......//查询了多少字段就写多少个map.get方法。如果这还看不懂，我就真的没办法了。这要是在我们项目组，早就被开除了 
     <br>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;} 
     <br>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;} 
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     <span>回复于： 2015-10-23 08:41:23</span> 
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