1.4 变量和数据类型进阶

怼烎@ 2022-05-20 00:16 292阅读 0赞

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#include<iostream>
    #include<cstdio>
    using namespace std;
    int main()
    {
    	int n1 = 1378;
    	short n2;
    	char c = 'a';
    	double d1 = 7.809;
    	double d2;
    	n2 = c+1;//n2=98
    	printf("c=%c,n2=%d\n",c,n2);//a,98
    	c = n1;//c=1378
    	printf("c=%c,n1=%d\n",c,n1);
    	n1 = d1;//n1=7
    	printf("n1=%d\n",n1);
    	d2 = n1;//7.000000
    	printf("d2=%f\n",d2);
    	return 0;
    }
    /*
    c=a,n2=98
    c=b,n1=1378
    n1=7
    d2=7.000000
    */

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【解释】c=n1，c为字符，占据一个字节，n1=1378=0x562(16)，因此c=0x62（16）=![70 9][]

，丢失一个5.

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[70 2]: https://img-blog.csdn.net/20180709133623259?watermark/2/text/aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3lhbnlhbndlbm1lbmc=/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70
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[70 5]: https://img-blog.csdn.net/20180709133943296?watermark/2/text/aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3lhbnlhbndlbm1lbmc=/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70
[70 6]: https://img-blog.csdn.net/20180709133952314?watermark/2/text/aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3lhbnlhbndlbm1lbmc=/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70
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