Python实例 -- 收发邮件

叁歲伎倆 2022-04-10 10:43 326阅读 0赞

[Python实例 -- 收发邮件][Python_ --] *2012-09-12 20:17:49*

分类： LINUX

python发邮件

1.  \#!/usr/bin/env python3  
    
2.  \#coding: utf\-8  
    
3.  import smtplib  
    
4.  from email.mime.text import MIMEText  
    
5.  from email.header import Header  
    
6.      
    
7.  sender = '\*\*\*'  
    
8.  receiver = '\*\*\*'  
    
9.  subject = 'python email test'  
    
10. smtpserver = 'smtp.163.com'  
    
11. username = '\*\*\*'  
    
12. password = '\*\*\*'  
    
13.     
    
14. msg = MIMEText('你好','plain','utf-8')\#中文需参数‘utf\-8’，单字节字符不需要  
    
15. msg\['Subject'\] = Header(subject, 'utf-8')  
    
16.     
    
17. smtp = smtplib.SMTP()  
    
18. smtp.connect('smtp.163.com')  
    
19. smtp.login(username, password)  
    
20. smtp.sendmail(sender, receiver, msg.as\_string())  
    
21. smtp.quit()

python收邮件

1.  \#!/usr/bin/env python3 
2.  \# \-\*\- coding: utf\-8 \-\*\-  
    
3.          
    
4.      import poplib  
    
5.      from email  import parser  
    
6.          
    
7.      host = 'pop.gmail.com'  
    
8.      username =  'mine@gmail.com'  
    
9.      password =  '\*\*\*\*\*\*\*'  
    
10.         
    
11.     pop\_conn = poplib.POP3\_SSL(host)  
    
12.     pop\_conn.user(username)  
    
13.     pop\_conn.pass\_(password)  
    
14.         
    
15.     \#Get messages from server:  
    
16.     messages =  \[pop\_conn.retr(i) for i in range(1, len(pop\_conn.list()\[1\]) \+ 1)\]  
    
17.         
    
18.     \# Concat message pieces:  
    
19.     messages =  \["\\n".join(mssg\[1\]) for mssg in messages\]  
    
20.         
    
21.     \#Parse message intom an email object:  
    
22.     messages =  \[parser.Parser().parsestr(mssg) for mssg in messages\]  
    
23.     for message  in messages:  
    
24.         print message\['Subject'\]  
    
25.     pop\_conn.quit()

[Python_ --]: http://blog.chinaunix.net/uid-26922865-id-3346337.html